has_prohibited_substring_after_sums

Checks if a string has a prohibited substring after given sums.

Related Packages

https://github.com/pelevesque/has_required_substrings_after_sums
https://github.com/pelevesque/has_required_substrings
https://github.com/pelevesque/has_prohibited_substring
https://github.com/pelevesque/has_required_substrings_at_indexes
https://github.com/pelevesque/has_prohibited_substring_at_indexes

Node Repository

https://www.npmjs.com/package/@pelevesque/has_prohibited_substring_after_sums

Installation

npm install @pelevesque/has_prohibited_substring_after_sums

Tests

Standard Style & Unit Tests

npm test

Unit Tests & Coverage

npm run cover

Usage

Parameters

str                  (required)
prohibitedSubstrings (required)
options              (optional) default = { substringsToDigits = null, sumPlainDigits = true, allowLastSubstringToBleed = false }

Requiring

const hasProhibitedSubstringAfterSums = require('@pelevesque/has_prohibited_substring_after_sums')

Basic Usage

@see https://github.com/pelevesque/sum-digits to understand how the sum is calculated.

prohibitedSubstrings is an object of sum -> substring pairs. true is returned if at least one substring is found following its associated sum but before the following sum.

const str = '123a45'
const prohibitedSubstrings = { 1: 'a' }
const result = hasProhibitedSubstringAfterSums(str, prohibitedSubstrings)
// result === false

const str = '123a45'
const prohibitedSubstrings = { 6: 'a' }
const result = hasProhibitedSubstringAfterSums(str, prohibitedSubstrings)
// result === true

const str = '123bca45'
const requiredSubstrings = { 6: 'a' }
const result = hasRequiredSubstringsAfterSums(str, requiredSubstrings)
// result === true

// only one substring needs to match
const str = '123man45adinosaur'
const prohibitedSubstrings = { 6: 'man', 150: 'dinosaur' }
const result = hasProhibitedSubstringAfterSums(str, prohibitedSubstrings)
// result === true

Options

substringsToDigits

You can use the substringsToDigits option to give numeric values to substrings so that they are counted during summing.

const str = '123!$$$a'
const prohibitedSubstrings = { 15: 'a' }
const substringsToDigits = { '!': 4, '$$$': 5 }
const result = hasProhibitedSubstringAfterSums(str, prohibitedSubstrings, {
  substringsToDigits: substringsToDigits
})
// result === true

sumPlainDigits

You can set the sumPlainDigits option to false if you only want to sum substringsToDigits.

In the following example, 1, 2, and 3 are not summed.

const str = '123!a'
const prohibitedSubstrings = { 4: 'a' }
const substringsToDigits = { '!': 4 }
const sumPlainDigits = false
const result = hasProhibitedSubstringAfterSums(str, prohibitedSubstrings, {
  substringsToDigits: substringsToDigits,
  sumPlainDigits: sumPlainDigits
})
// result === true

allowLastSubstringToBleed

The allowLastSubstringToBleed option is false by default. It it used when you want to allow the last substring to be incomplete if the string is too short. In the following example, the last substring canal starts at the correct index, but remains incomplete since the string ends. Normally this would return false. With allowLastSubstringToBleed set to true, it returns true.

const str = '123can'
const prohibitedSubstrings = { 6: 'canal' }
const allowLastSubstringToBleed = true
const result = hasProhibitedSubstringAfterSums(str, prohibitedSubstrings, {
  allowLastSubstringToBleed: allowLastSubstringToBleed
})
// result === true