alps-unified-ts
v0.0.40
Published
[](https://badge.fury.io/js/alps-unified-ts) [](https://badge.fury.io/py/alps-unified-ts) [
Examples
Load from YAML file
You can load the ALPS spec directly from a YAML file. JSON ist atm not supported.
Convert to OpenApi
Alps.unified(Alps.loadYaml('test/todo-alps.yaml'), {
formatType: FormatType.OPENAPI,
});Convert to GraphQL Schema
Alps.unified(Alps.loadYaml('test/todo-alps.yaml'), {
formatType: FormatType.SDL,
});Create from Spec
Creating the API specification from the spec is very powerful. As it gives you much support in an idea like VS as it is typed and documented. So you alway produce valid API specs.
Alps.unified(
Alps.spec({
alps: {
version: '1.0',
doc: {
value: 'Simple Todo list example',
},
ext: [
{
type: 'metadata',
name: 'title',
value: 'simpleTodo',
tags: 'oas',
},
{
type: 'metadata',
name: 'root',
value: 'http://api.example.org/todo',
tags: 'oas',
},
],
descriptor: [
{
id: 'id',
type: 'semantic',
text: 'storage id of todo item',
},
],
},
}),
);For Python to benefit from the types better do this:
import alps_unified_ts as alps
alps_def = alps.AlpsDef(
version='1.0',
descriptor=[alps.DescriptorDef(id="id", type="semantic", text="sotrage id of todo item")],
doc=alps.DocDef(
value="Simple Todo list example"),
ext=[
alps.ExtDef(
name="root",
tags="oas",
type="metadata",
value="http://api.example.org/todo"),
alps.ExtDef(
name="title",
tags="oas",
type="metadata",
value="simpleTodo")])
alps.Alps.unified(alps_document=alps.Alps.spec(alps=alps_def), format_type=alps.FormatType.OPENAPI)Thanks to
- The AWS CDK Community for the repo tool projen which I use for this repo.
