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custom-url-check

v1.3.0

Published

๐Ÿœ Simple NPM package to check if a string is valid and a specific community URL!

Downloads

31

Readme

custom-url-check

  • Simple NPM package to check a string for a valid custom filtered URL!
  • See examples below

Install via NPM

$ npm i custom-url-check

Usage

  • Returns a Boolean indicating whether string is a valid URL and contains the specified community filter
  • filter parameter is case-insensitive
const customUrl = require('custom-url-check');

// --| customURL(url, filter);
// --| The below URL is not a valid YouTube URL
customUrl('amazon.co.uk', 'youtube');
customUrl('www.google.pl', 'YouTube');
customUrl('https://www.github.com', 'youtube');

// --| customURL(url, filter);
// --| The below URL is a valid YouTube URL
customUrl('https://www.youtube.com/', 'YouTube');
customUrl('www.youtube.com', 'youtube');
customUrl('youtube.com', 'YouTUBE');
customUrl('https://www.youtube.com/watch?v=w3jLJU7DT5E', 'Youtube');

Example

const customUrl = require('custom-url-check');

const testUrl = [
    'https://www.npmjs.com/',
    'www.googl.co.uk',
    'www.youtube.ro',
    'http://google.com',
    'https://www.google.com',
    'http://www.google.com',
    'www.google.com',
    'google.com'
];

testUrl.forEach((element) => {
    if (customUrl(element, 'GoOgLe')) {
        console.log(element + ' It\'s a valid Google URL! โœ…');
    }

    else {
        console.log(element + ' Is not a valid Google URL! โŒ');
    }
});

Result of the example above