Simple Data

主要是集合的处理，收集一些以及工作中用到过，或者会用到的一些集合处理方法，不喜勿喷，励志做一个合格的小开发

let a = [ {"a":"aaaa", "b": "bbbbbbb", "c": "cccccccccccc", "d": "dddddddddd", e: "test", f: "1ee", num: 12, num1: -45}, {"a":"wer", "b": "11313", "c": "s3fdd", "d": "041", e: "e", f: "f",num: 3, num1: -60}, {"a":"aa", "b": "bb", "c": "cc", "d": "dd", num: 100, num1: 2}, {"a":"aa1", "b1": "bb1", "c1": "cc1", "d1": "dd1", num: 100, num1: 21}, {"a":"a112", "b": "b11", "c": "c00", "d": "dkc", e: "test", f: "test1",num: -100, num1: 1}, {"a":"aa", "b": "bb", "c": "000", "d00": "7800", e: "e", f: "0f0",num: -10, num1: 10}, {"a":"aa", "b": "bb", "c": "asd", "d": "dd", e: "eyt", f: "0f0",num: -17, num1: 11}, {"a":"f", "b": "u", "c": "c", "d": "k", e: "!", f: "!!",num: 5, num1: 5} ];

let b = [2,"ad", undefined,null,"2", 2, 4, 5, "e12", 1, 3, 3, 2, "sdf", "12",null, undefined,"fuck", "fuckup", "sdf"]

let b_1 = [100,"qwe", "as","sd",-911, 2, "12ds","sd","fd","ds","as","sd","dx1","100t","50g","128g","256g","100t","100","1001","1022"]

let b_2 = [12,343,44,33,-132,0,-1,31,3,4,65,-9,0,3,11,1,2]

let b_3 = ['12', '3430', '44', 33, '-132', 0, -1, 31, 3, '4', 65, -9, 0, '3', 11, '1', '2', 0, undefined, false, null,NaN,'']

let c = [ {name:"dragon", win:3, lose:2, status: false}, {name:"jack", win:3.5, lose:1, status: false}, {name:"ben", win:1, lose:1.5, status: true}, {name:"skip", win:4, lose:0.5, status: false}, {name:"bobi", win:1.1, lose:1.6, status: true} ]

let d = [ // { // title: "dragon", num: 440, children: [{money: "25000", time: 12},{money: "25000", time: 13},{money: "25000", time: 6}] // }, // { // title: "jack", num: 227, children: [{money: "35000", time: 48},{money: "25000", time: 24},{money: "25000", time: 36}] // }, // { // title: "ben", num: 428, children: [{money: "30000", time: 31},{money: "30000", time: 22},{money: "25000", time: 100000}] // }, { title: "skip", num: 428, children: [ {base: "2019", angele: true, child: [ {time: 324}, {time: 100}, {time: 475} ]} ] }, { title: "duck", num: 338, children: [ {base: "2017", angele: true, child: [ {time: 3424}, {time: 70}, {time: 71} ]} ] } ]

data_item_array

data_item_number

数组里的元素为 number 元素

最大值 getMax: true

最小值 getMin: true

simpArr_Num(b_3, {getMax: true, getMin: true});

data_item_string

数组里的元素为 string 元素

去重 repeat:true

得到集合每个元素出现的次数 same: true ，100 和 "100" 视为同一个

simpArr_Str(b_1, {same: true, repeat:true});

data_item_object

数组里的元素为 object 元素

为每个item添加索引：key:true （渲染列表时有时需要key=index）

filterObj: {[key]:[value]} 筛选得到，对应所出现的item阵列：{e: [{……}，{……}], f: …… ……, filterIndex;[]} ，filterResult为出现的索引集合

sortKey:[arg1, arg2] 排序默认取arg1的值排序，相同值的话则取arg2的值排序

direction: "asc" | "desc" 排序字段是升序还是降序，一定要配合sortKey使用, 因为要匹配 sortKey:[] 里的key

repeatKeys: ["a", "b","f"] 以repeatKeys里的元素为key取得每条item对应key的value值，拼接在一起，查看是否有相同的 repeatKeysResult["res"]为最终不重复的集合，repeatKeysResult["repeat"]为筛选出重复的item

max:["num"]: 得到数组里[num]对应key的最大值的那条item

min:["num"]: 得到数组里[num]对应key的最小值的那条item

keyVlaue:{key:"title", value:"time", child:["children", "child"]} key对应最终返回的对象那个Key，value对应的是你所要取的值那个Key, child对应你所要遍历几层才能拿到value

selectAmountKey: [key, key] key是数组单个元素里对应的key , 最终计算出数组元素以key的值为参考，得到[value]出现的次数

simpArr_Obj(a, {
    key:true, 
    filterObj:{e: "test",f: "0f0"}, 
    sortKey:["num", "num1"],
    direction: "asc",   //升序和降序 Ascending Descending
    repeatKeys: ["a", "b","f"],
    max:["num"], 
    min:["num"] 
})

simpArr_Obj(d, {
    keyVlaue: {key: "title", value: "time", child: ["children", "child"]}
})

SetArray()

不断往数组里unshift最新的元素，并且不能有重复的，不能超过设定长度

setArray.spliceItem(33, 4)：预想阵列length为4，传入第一个数为33,后续继续调用方法传入，每次传入unshift到阵列的第0个,如果下次传入的值在之前的阵列里存在，就把之前那个旧值删掉，新值依旧unshift在第0个,之后查看最新的阵列是否大于length为4,如果大于则切掉后面多余的

setArray.spliceItem(obj, key, length)：预想阵列长度length，obj为预想插入的itemObj, key为预想用来判断的[key]:[value]

const setArray = new SetArray();

const { spliceItem, spliceObjItem } = setArray;

SetBroad()

广播效果，排序，以及类似主播开和关的socket推送

sortObjItem(c, "status"): 上面定义的c数组，以"status"为key排序，筛选出true或false的值

subscribeMes(msg, "status", "name"): 接收一条msgObj, 通过"status", "name"为key的对应的值，来改变原数组对应name的status值，类似于主播开播和关播的推送状态到前端

const setBroad = new SetBroad();

const {sortObjItem, subscribeMes, resSort: {active, other, result}} = SetBroad();

var msg = {name:"jack", status: true}

var msg1 = {name:"skip", status: true}

var msg2 = {name:"ben", status: false}

sortObjItem(c, "status") 需要先`sort`一遍

setBroad.subscribeMes(msg, "status", "name")
setBroad.subscribeMes(msg1, "status", "name")
setBroad.subscribeMes(msg2, "status", "name")