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typage-url

v1.0.1

Published

Make your URL type-safe!

Readme

typage-url

Actions Status

Make your URL type-safe by leveraging the power of TypeScript!

Notification

  1. TypeScript version need to be above 4.1.0.

Usage

Create the path object by passing in a object which represents your route tree recursively:

import { createPath, END } from 'typage-url';

const root = createPath({
  page1: {},
  page2: {
    [END]: true,
    subpage1: {}
  },
  page3: {
    subpage1: {}
  }
});

The example above creates a path object which can form the following urls:

  • /page1
  • /page2
  • /page2/subpage1
  • /page3/subpage1

You can use the build function from the library to get all the available urls:

import { createPath, END, build } from 'typage-url';

const root = createPath({
  page1: {},
  page2: {
    [END]: true,
    subpage1: {}
  },
  page3: {
    subpage1: {}
  }
});

build(root.page1); // => '/page1'
build(root.page2); // => '/page2'
build(root.page2.subpage1); // => '/page2/subpage1'
build(root.page3); // throws type error for unavailable url
build(root.page3.subpage1); // => '/page3/subpage1'

For url with path parameters, just name the path with prefix ':', for example:

const root = createPath({
  users: {
    ':id': {}
  }
});

And the path object will automatically generate a value getter for that path as a function:

const root = createPath({
  users: {
    ':id': {}
  }
});

build(root.users.id('123')); // => '/users/123'

If you don't pass in the value, the returned url will just keep the path parameter template there, this is useful when doing routing configurations using other libraries like react-router:

build(root.users.id); // => '/users/:id'

A prefix for all the generated urls is possible, you can pass in your prefix as the second parameter of the createPath function:

const root = createPath(
  {
    page1: {},
    page2: {}
  },
  '/the/prefix'
);

build(root.page1); // => '/the/prefix/page1'
build(root.page2); // => '/the/prefix/page2'